A simple utility class that will help you convert a color value (from numbers) to hexadecimal color value.

Basically you can convert the color value to hex string with colorNumber.toString(16);
Now, if you have this shade of blue “13311”, for example, it will be converted to “33ff”.

You can fix that with while(hexColor.length < 6) and add “0” to in front of the hex color output.

Today I’m sharing with you a little utility that I find myself using a lot lately. This utility is a value convertor that you can use in those times when you need to make a volume slider or something similar where you’ll need to change a value and a value range.

package com.vamapaull.utils
{	
	public class ValueConvertor
	{
		public static function convertRange(originalStart:Number, 
							originalEnd:Number, 
							newStart:Number, 
							newEnd:Number, 
							value:Number):Number
		{
			var originalRange:Number = originalEnd - originalStart;
			var newRange:Number = newEnd - newStart;
			var ratio:Number = newRange / originalRange;
			var newValue:Number = value * ratio;
			var finalValue:Number = newValue + newStart;
			return finalValue;
		}
	}
}

I was making a project for a client of mine where I had to make a list with two different colors for the items (like the iTunes list) so I started to think of a possible way to make this. It was clear enough I need to know the odd or the even number in order to do that. So I started to do some google search and I got over this blogpost by Keith Peters. I have to say, this is a very interesting way of thinking 😀

“iseven = ((num & 1) == 0)

Makes sense when you look at binary numbers:

001 = 1
010 = 2
011 = 3
100 = 4
101 = 5

Each of the odd numbers has a 1 in the far right column. The even numbers have 0 there. Mask it with “& 1″ and you can see which it is.”

So I made a for loop and used this code. It works exactly how it was intended to work!!
Thanks Keith Peters for your blogpost 😀

Today I had this little problem. I needed to generate a random number from 1 to 30 and the result had to except a specific number (as in this example, any number from 1 to 30 except the number 7 )
The code is done now, it’s working as it should and I posted it in case someone else needs this same code.

var randomNumber:Number;
var minNumber:Number = 1;
var maxNumber:Number = 30;
 
function generateRandomNumber():void{
	randomNumber = Math.round(Math.random() * (maxNumber - minNumber)) + minNumber;
	if(randomNumber == 7){
		generateRandomNumber();
	}
	trace(randomNumber)
}
generateRandomNumber();

By the way, the code here is ActionScript 3 but if you remove “:void” you can use it in ActionScript 2 too 😉